Easy methods to Discover the Smallest Integer within the Array in Golang

The problem

Given an array of integers your resolution ought to discover the smallest integer.

For instance:

• Given [34, 15, 88, 2] your resolution will return 2
• Given [34, -345, -1, 100] your resolution will return -345

You possibly can assume, for the aim of this problem, that the equipped array won’t be empty.

The answer in Golang

Choice 1:

package deal resolution
func SmallestIntegerFinder(numbers []int) int {
  curr := numbers[0]
  for _, v := vary numbers {
    if v<curr {
      curr = v
    }
  }
  return curr
}

Choice 2:

package deal resolution
import "type"
func SmallestIntegerFinder(numbers []int) int {
  type.Ints(numbers)
  return numbers[0]
}

Choice 3:

package deal resolution
func SmallestIntegerFinder(numbers []int) int {  
  return quickSort(numbers)[0]
}
func quickSort( enter []int) []int{
  if len(enter)==0 {
    return []int{}
  }
  index:=len(enter)/2
  temp:=enter[index]
  var decrease []int
  var higher []int
  for i:= vary enter{
    if i==index {
      proceed
    }
    if enter[i] <= temp {
      decrease = append(decrease, enter[i])
    } else {
      higher = append(higher, enter[i])
    }
  }
  consequence:=append(quickSort(decrease), temp)
  return append(consequence, quickSort(higher)...)
}

Check circumstances to validate our resolution

package deal solution_test
import (
  . "github.com/onsi/ginkgo"
  . "github.com/onsi/gomega"
  "math/rand"
  "type"
  "time"
)
func _solution(numbers []int) int {
  type.Ints(numbers)
  return numbers[0]
}
var _ = Describe("Check Instance", func() {
  It("ought to work for pattern assessments", func() {
    Anticipate(Anticipate(SmallestIntegerFinder([]int{34, 15, 88, 2})).To(Equal(2)))
    Anticipate(Anticipate(SmallestIntegerFinder([]int{34, -345, -1, 100})).To(Equal(-345)))
  })
  rand.Seed(time.Now().UTC().UnixNano())
  min, max := -100, 100
  It("ought to work for random assessments", func() {
    for i := 0; i < 500; i++ {
      arrLen := 10 + rand.Intn(100)
      var arrInts []int
      for j := 0; j < arrLen; j++ {
        arrInts = append(arrInts, rand.Intn(max - min + 1) + min)
      }
      ts := SmallestIntegerFinder(arrInts)
      r := _solution(arrInts)
      Anticipate(ts).To(Equal(r))
    }
  })
})